CBSE Class 12 Mathematics Inverse Trigonometric Functions VBQs Set 04

Read and download the CBSE Class 12 Mathematics Inverse Trigonometric Functions VBQs Set 04. Designed for the 2026-27 academic year, these Value Based Questions (VBQs) are important for Class 12 Mathematics students to understand moral reasoning and life skills. Our expert teachers have created these chapter-wise resources to align with the latest CBSE, NCERT, and KVS examination patterns.

VBQ for Class 12 Mathematics Chapter 2 Inverse Trigonometric Functions

For Class 12 students, Value Based Questions for Chapter 2 Inverse Trigonometric Functions help to apply textbook concepts to real-world application. These competency-based questions with detailed answers help in scoring high marks in Class 12 while building a strong ethical foundation.

Chapter 2 Inverse Trigonometric Functions Class 12 Mathematics VBQ Questions with Answers

Question. If \( \cos \left( \sin^{-1} \frac{2}{5} + \cos^{-1} x \right) = 0 \), then \( x \) is equal to : 
(a) \( \frac{1}{5} \)
(b) \( \frac{2}{5} \)
(c) \( 0 \)
(d) \( 1 \)
Answer: (b) \( \frac{2}{5} \)

 

Question. Which of the following corresponds to the principal value branch of \( \tan^{-1} x \)?
(a) \( \left( -\frac{\pi}{2}, \frac{\pi}{2} \right) \)
(b) \( \left[ -\frac{\pi}{2}, \frac{\pi}{2} \right] \)
(c) \( \left( -\frac{\pi}{2}, \frac{\pi}{2} \right) - \{0\} \)
(d) \( (0, \pi) \)
Answer: (a) \( \left( -\frac{\pi}{2}, \frac{\pi}{2} \right) \)

 

Question. The principal value branch of \( \sec^{-1} x \) is:
(a) \( \left[ -\frac{\pi}{2}, \frac{\pi}{2} \right] - \{0\} \)
(b) \( [0, \pi] - \{ \frac{\pi}{2} \} \)
(c) \( (0, \pi) \)
(d) \( \left( -\frac{\pi}{2}, \frac{\pi}{2} \right) \)
Answer: (b) \( [0, \pi] - \{ \frac{\pi}{2} \} \)

 

Question. The principal value of the expression \( \cos^{-1} [\cos (-680^\circ)] \) is :
(a) \( \frac{2\pi}{9} \)
(b) \( -\frac{2\pi}{9} \)
(c) \( \frac{34\pi}{9} \)
(d) \( \frac{\pi}{9} \)
Answer: (a) \( \frac{2\pi}{9} \)

 

Question. The value of \( \cot (\sin^{-1} x) \) is:
(a) \( \frac{\sqrt{1+x^2}}{x} \)
(b) \( \frac{x}{\sqrt{1+x^2}} \)
(c) \( \frac{1}{x} \)
(d) \( \frac{\sqrt{1-x^2}}{x} \)
Answer: (d) \( \frac{\sqrt{1-x^2}}{x} \)

 

Question. The domain of \( \sin^{-1} 2x \) is:
(a) \( [0, 1] \)
(b) \( [-1, 1] \)
(c) \( [-\frac{1}{2}, \frac{1}{2}] \)
(d) \( [-2, 2] \)
Answer: (c) \( [-\frac{1}{2}, \frac{1}{2}] \)

 

Question. The principal value of \( \sin^{-1} \left( -\frac{\sqrt{3}}{2} \right) \) is:
(a) \( -\frac{2\pi}{3} \)
(b) \( -\frac{\pi}{3} \)
(c) \( \frac{4\pi}{3} \)
(d) \( \frac{5\pi}{3} \)
Answer: (b) \( -\frac{\pi}{3} \)

 

Question. The domain of \( y = \cos^{-1} (x^2 - 4) \) is:
(a) \( [3, 5] \)
(b) \( [0, \pi] \)
(c) \( [-\sqrt{5}, -\sqrt{3}] \cap [\sqrt{3}, \sqrt{5}] \)
(d) \( [-\sqrt{5}, -\sqrt{3}] \cup [\sqrt{3}, \sqrt{5}] \)
Answer: (d) \( [-\sqrt{5}, -\sqrt{3}] \cup [\sqrt{3}, \sqrt{5}] \)

 

Question. The domain of the function defined by \( f(x) = \sin^{-1} x + \cos x \) is:
(a) \( [-1, 1] \)
(b) \( [-1, \pi + 1] \)
(c) \( (-\infty, \infty) \)
(d) \( \phi \)
Answer: (a) \( [-1, 1] \)

 

Question. The value of \( \sin [2 \sin^{-1} (0.6)] \) is:
(a) \( 0.48 \)
(b) \( 0.96 \)
(c) \( 1.2 \)
(d) \( \sin 1.2 \)
Answer: (b) \( 0.96 \)

 

Question. The value of \( \tan \left\{ \cos^{-1} \frac{1}{5\sqrt{2}} - \sin^{-1} \frac{4}{\sqrt{17}} \right\} \) is :
(a) \( \frac{\sqrt{29}}{3} \)
(b) \( \frac{29}{3} \)
(c) \( \frac{\sqrt{3}}{29} \)
(d) \( \frac{3}{29} \)
Answer: (d) \( \frac{3}{29} \)

 

Question. If \( \cot^{-1} \left( -\frac{1}{5} \right) = \theta \), the value of \( \sin \theta \) is :
(a) \( \frac{\sqrt{26}}{5} \)
(b) \( -\frac{5}{\sqrt{26}} \)
(c) \( \frac{\sqrt{5}}{\sqrt{26}} \)
(d) \( \frac{5}{\sqrt{26}} \)
Answer: (d) \( \frac{5}{\sqrt{26}} \)

 

Question. If \( \alpha \le 2 \sin^{-1} x + \cos^{-1} x \le \beta \), then:
(a) \( \alpha = -\frac{\pi}{2}, \beta = \frac{\pi}{2} \)
(b) \( \alpha = 0, \beta = \pi \)
(c) \( \alpha = -\frac{\pi}{2}, \beta = \frac{3\pi}{2} \)
(d) \( \alpha = 0, \beta = 2\pi \)
Answer: (b) \( \alpha = 0, \beta = \pi \)

 

Question. The value of \( \tan^2 (\sec^{-1} 2) + \cot^2 (\text{cosec}^{-1} 3) \) is:
(a) \( 5 \)
(b) \( 11 \)
(c) \( 13 \)
(d) \( 15 \)
Answer: (b) \( 11 \)

 

Question. The value of \( \tan \left[ \frac{1}{2} \cos^{-1} \left( \frac{\sqrt{5}}{3} \right) \right] \) is : 
(a) \( \frac{3 + \sqrt{5}}{2} \)
(b) \( \frac{3 - \sqrt{5}}{2} \)
(c) \( \frac{-3 + \sqrt{5}}{2} \)
(d) \( \frac{-3 - \sqrt{5}}{2} \)
Answer: (b) \( \frac{3 - \sqrt{5}}{2} \)

 

Question. The principal value of \( \tan^{-1} \left( \frac{1}{\sqrt{3}} \right) \) is:
(a) \( \frac{\pi}{2} \)
(b) \( \frac{\pi}{6} \)
(c) \( \frac{\pi}{3} \)
(d) \( \pi \)
Answer: (b) \( \frac{\pi}{6} \)

 

Question. The principal value of \( \sec^{-1} \left( -\frac{2}{\sqrt{3}} \right) \) is :
(a) \( \frac{5\pi}{6} \)
(b) \( \frac{2\pi}{3} \)
(c) \( \frac{\pi}{3} \)
(d) None of the options
Answer: (a) \( \frac{5\pi}{6} \)

 

Question. The inverse of cosine function is defined in the intervals :
(a) \( [-\pi, 0] \)
(b) \( [-\frac{\pi}{2}, 0] \)
(c) \( [0, \frac{\pi}{2}] \)
(d) \( [\frac{\pi}{2}, \pi] \)
Answer: (a) \( [-\pi, 0] \)

 

Question. If \( \sin^{-1} x = y \), then :
(a) \( 0 \le y \le x \)
(b) \( -\frac{\pi}{2} \le y \le \frac{\pi}{2} \)
(c) \( 0 < y < \pi \)
(d) \( -\frac{\pi}{2} < y < \frac{\pi}{2} \)
Answer: (b) \( -\frac{\pi}{2} \le y \le \frac{\pi}{2} \)

 

Question. \( \sin \left( \frac{\pi}{3} - \sin^{-1} \left( -\frac{1}{2} \right) \right) \) is equal to :
(a) \( 1/2 \)
(b) \( 1/3 \)
(c) \( 1/4 \)
(d) \( 1 \)
Answer: (d) \( 1 \)

 

Question. The value of \( \tan^{-1} \left( -\frac{1}{\sqrt{3}} \right) + \cot^{-1} \left( \frac{1}{\sqrt{3}} \right) + \tan^{-1} \left( \sin \left( -\frac{\pi}{2} \right) \right) \) is :
(a) \( \frac{\pi}{6} \)
(b) \( \frac{\pi}{12} \)
(c) \( -\frac{\pi}{12} \)
(d) \( -\frac{\pi}{2} \)
Answer: (c) \( -\frac{\pi}{12} \)

 

Question. The value of \( \tan^{-1} \left[ 2 \sin \left( 2 \cos^{-1} \frac{\sqrt{3}}{2} \right) \right] \) is :
(a) \( \frac{\pi}{3} \)
(b) \( \frac{2\pi}{3} \)
(c) \( -\frac{\pi}{3} \)
(d) \( \frac{\pi}{6} \)
Answer: (a) \( \frac{\pi}{3} \)

 

Question. The value of \( \tan^{-1} \left( \tan \frac{5\pi}{6} \right) + \cos^{-1} \left( \cos \frac{13\pi}{6} \right) \) is :
(a) \( 0 \)
(b) \( \frac{\pi}{3} \)
(c) \( \frac{\pi}{6} \)
(d) \( \frac{2\pi}{3} \)
Answer: (a) \( 0 \)

 

Question. The domain of the function \( \cos^{-1} (2x - 1) \) is :
(a) \( [0, 1] \)
(b) \( [-1, 1] \)
(c) \( (-1, 1) \)
(d) \( [0, \pi] \)
Answer: (a) \( [0, 1] \)

 

Question. The domain of the function defined by \( f(x) = \sin^{-1} \sqrt{x - 1} \) is : 
(a) \( [1, 2] \)
(b) \( [-1, 1] \)
(c) \( [0, 1] \)
(d) None of the options
Answer: (a) \( [1, 2] \)

 

Question. The value of \( \cos^{-1} \left( \cos \frac{3\pi}{2} \right) \) is equal to : 
(a) \( \frac{\pi}{2} \)
(b) \( \frac{3\pi}{2} \)
(c) \( \frac{5\pi}{2} \)
(d) \( \frac{7\pi}{2} \)
Answer: (a) \( \frac{\pi}{2} \)

 

Question. Solve \( \sin (\tan^{-1} x), |x| < 1 \) is equal to :
(a) \( \frac{x}{\sqrt{1-x^2}} \)
(b) \( \frac{1}{\sqrt{1-x^2}} \)
(c) \( \frac{1}{\sqrt{1+x^2}} \)
(d) \( \frac{x}{\sqrt{1+x^2}} \)
Answer: (d) \( \frac{x}{\sqrt{1+x^2}} \)

 

Assertion and Reason Questions

Choose the correct option :
(a) Both (A) and (R) are true and R is the correct explanation A.
(b) Both (A) and (R) are true but R is not correct explanation of A.
(c) A is true but R is false.
(d) A is false but R is true.

 

Question. Assertion (A) : \( \sin^{-1} (\sin 3) = 3 \)
Reason (R) : For principal values \( \sin^{-1} (\sin x) = x \)

(a) (a)
(b) (b)
(c) (c)
(d) (d)
Answer: (d) A is false but R is true.

 

Question. Assertion (A) : The solution of system of equations \( \cos^{-1} x + (\sin^{-1} y)^2 = \frac{p\pi^2}{4} \) and \( (\cos^{-1} x)(\sin^{-1} y)^2 = \frac{\pi^4}{16} \) is \( x = \cos \frac{\pi^2}{4} \) and \( y = \pm 1 \), \( \forall p \in I \).
Reason (R) : \( AM \ge GM \)

(a) (a)
(b) (b)
(c) (c)
(d) (d)
Answer: (a) Both (A) and (R) are true and R is the correct explanation A.

 

Question. Assertion (A) : If \( \sum_{i=1}^{2n} \sin^{-1} x_i = n\pi, n \in N \). Then, \( \sum_{i=1}^{2n} x_i = \sum_{i=1}^{2n} x_i^2 = \sum_{i=1}^{2n} x_i^3 = n \)
Reason (R) : \( -\frac{\pi}{2} \le \sin^{-1} x \le \frac{\pi}{2}, \forall x \in [-1, 1] \)

(a) (a)
(b) (b)
(c) (c)
(d) (d)
Answer: (a) Both (A) and (R) are true and R is the correct explanation A.

 

Question. Assertion : The equation \( 2(\sin^{-1} x)^2 - 5(\sin^{-1} x) + 2 = 0 \).
Reason : \( \sin^{-1} (\sin x) = x \) if \( x \in [-1.57, 1.57] \).

(a) (a)
(b) (b)
(c) (c)
(d) (d)
Answer: (d) A is false but R is true.

 

VBQs for Chapter 2 Inverse Trigonometric Functions Class 12 Mathematics

Students can now access the Value-Based Questions (VBQs) for Chapter 2 Inverse Trigonometric Functions as per the latest CBSE syllabus. These questions have been designed to help Class 12 students understand the moral and practical lessons of the chapter. You should practicing these solved answers to improve improve your analytical skills and get more marks in your Mathematics school exams.

Expert-Approved Chapter 2 Inverse Trigonometric Functions Value-Based Questions & Answers

Our teachers have followed the NCERT book for Class 12 Mathematics to create these important solved questions. After solving the exercises given above, you should also refer to our NCERT solutions for Class 12 Mathematics and read the answers prepared by our teachers.

Improve your Mathematics Scores

Daily practice of these Class 12 Mathematics value-based problems will make your concepts better and to help you further we have provided more study materials for Chapter 2 Inverse Trigonometric Functions on studiestoday.com. By learning these ethical and value driven topics you will easily get better marks and also also understand the real-life application of Mathematics.

FAQs

Where can I find 2026-27 CBSE Value Based Questions (VBQs) for Class 12 Mathematics Chapter Chapter 2 Inverse Trigonometric Functions?

The latest collection of Value Based Questions for Class 12 Mathematics Chapter Chapter 2 Inverse Trigonometric Functions is available for free on StudiesToday.com. These questions are as per 2026 academic session to help students develop analytical and ethical reasoning skills.

Are answers provided for Class 12 Mathematics Chapter Chapter 2 Inverse Trigonometric Functions VBQs?

Yes, all our Mathematics VBQs for Chapter Chapter 2 Inverse Trigonometric Functions come with detailed model answers which help students to integrate factual knowledge with value-based insights to get high marks.

What is the importance of solving VBQs for Class 12 Chapter Chapter 2 Inverse Trigonometric Functions Mathematics?

VBQs are important as they test student's ability to relate Mathematics concepts to real-life situations. For Chapter Chapter 2 Inverse Trigonometric Functions these questions are as per the latest competency-based education goals.

How many marks are usually allocated to VBQs in the CBSE Mathematics paper?

In the current CBSE pattern for Class 12 Mathematics, Chapter 2 Inverse Trigonometric Functions Value Based or Case-Based questions typically carry 3 to 5 marks.

Can I download Mathematics Chapter Chapter 2 Inverse Trigonometric Functions VBQs in PDF for free?

Yes, you can download Class 12 Mathematics Chapter Chapter 2 Inverse Trigonometric Functions VBQs in a mobile-friendly PDF format for free.