Practice Class 11 Mathematics Binomial Distribution MCQs Set 02 provided below. The MCQ Questions for Class 11 Chapter 7 Binomial Theorem Mathematics with answers and follow the latest CBSE/ NCERT and KVS patterns. Refer to more Chapter-wise MCQs for CBSE Class 11 Mathematics and also download more latest study material for all subjects
MCQ for Class 11 Mathematics Chapter 7 Binomial Theorem
Class 11 Mathematics students should review the 50 questions and answers to strengthen understanding of core concepts in Chapter 7 Binomial Theorem
Chapter 7 Binomial Theorem MCQ Questions Class 11 Mathematics with Answers
Question. The mean of binomial distribution is 6 and its S.D. is \( \sqrt{2} \), then the number of trials n is
(a) 7
(b) 8
(c) 9
(d) 10
Answer: (c) 9
Question. If a random variable X follows B.D. with mean 2.4 and variance 1.44, the number of independent trials n is
(a) 10
(b) 8
(c) 6
(d) 2
Answer: (c) 6
Question. If for a binomial distribution with n = 5, \( 4p(X=1)=P(X=2) \), the probability of success is
(a) \( \frac{1}{3} \)
(b) \( \frac{2}{3} \)
(c) \( \frac{1}{4} \)
(d) \( \frac{1}{8} \)
Answer: (b) \( \frac{2}{3} \)
Question. A symmetrical die is rolled 720 times. Getting a face with four points is considered to be a success. The mean and variance of the number of successes is
(a) 20, 120
(b) 120, 100
(c) 100, 100
(d) 50, 50
Answer: (b) 120, 100
Question. The probability of getting atleast two heads when an unbiased coin is tossed three times is
(a) \( \frac{1}{4} \)
(b) \( \frac{1}{3} \)
(c) \( \frac{1}{2} \)
(d) \( \frac{1}{8} \)
Answer: (c) \( \frac{1}{2} \)
Question. For a binomial distribution \( \bar{x} = 4, \sigma^2 = 3 \) then the distribution of x is
(a) \( \left(\frac{1}{4} + \frac{3}{4}\right)^{16} \)
(b) \( \left(\frac{3}{4} + \frac{1}{4}\right)^{16} \)
(c) \( \left(\frac{1}{2} + \frac{1}{2}\right)^{16} \)
(d) \( \left(\frac{1}{2} + \frac{1}{2}\right)^8 \)
Answer: (b) \( \left(\frac{3}{4} + \frac{1}{4}\right)^{16} \)
Question. If for a binomial distribution mean = \( \frac{10}{3} \) and sum of mean and variance is \( \frac{40}{9} \). The parameters are
(a) \( \frac{2}{3}, 10 \)
(b) \( \frac{2}{3}, 20 \)
(c) \( 5, \frac{2}{3} \)
(d) \( 4, \frac{2}{3} \)
Answer: (c) \( 5, \frac{2}{3} \)
Question. If for a binomial distribution \( \bar{x} = \frac{6}{5} \) and the difference between mean and variance is \( \frac{6}{25} \). The number of trials is
(a) 8
(b) 7
(c) 6
(d) 5
Answer: (c) 6
Question. If for a B.D. with n=12, the ratio of variance to mean is \( \frac{1}{3} \), the probability of 10 successes is
(a) \( ^{15}C_{10} \left(\frac{2}{3}\right)^{10} \left(\frac{1}{3}\right)^2 \)
(b) \( ^{12}C_{10} \left(\frac{2}{3}\right)^{10} \left(\frac{1}{3}\right)^2 \)
(c) \( \left(\frac{2}{3}\right)^{10} \)
(d) \( \left(\frac{1}{3}\right)^{10} \)
Answer: (b) \( ^{12}C_{10} \left(\frac{2}{3}\right)^{10} \left(\frac{1}{3}\right)^2 \)
Question. A symmetrical die is thrown three times. If getting a six is considered to be a success, the probability of atleast two successes is
(a) \( \frac{4}{27} \)
(b) \( \frac{3}{27} \)
(c) \( \frac{2}{27} \)
(d) \( \frac{1}{27} \)
Answer: (c) \( \frac{2}{27} \)
Question. If for a BD the mean is 6 and standard deviation is \( \frac{1}{\sqrt{2}} \), the probability of success is
(a) 11/12
(b) 10/12
(c) 9/12
(d) 8/12
Answer: (a) 11/12
Question. If the sum of mean and variance of B.D. for 5 trials is 1.8, the binomial distribution is
(a) \( (0.8 + 0.2)^5 \)
(b) \( (0.2 + 0.8)^5 \)
(c) \( (0.8 + 0.2)^{10} \)
(d) \( (0.2 + 0.8)^{10} \)
Answer: (a) \( (0.8 + 0.2)^5 \)
Question. If for a binomial distribution n = 4 and 6P(X=4)=P(X=2), the probability of success is
(a) 3/4
(b) 1/2
(c) 1/3
(d) 1/4
Answer: (b) 1/2
Question. A box contains 6 red and 4 white marbles. A marble is drawn and replaced three times from the box. The probability that one white marble is drawn
(a) \( \frac{53}{125} \)
(b) \( \frac{54}{125} \)
(c) \( \frac{56}{125} \)
(d) \( \frac{52}{125} \)
Answer: (b) \( \frac{54}{125} \)
Question. A random variable X is binomially distributed with mean is 12 and variance is 8. Find the parameters of the distribution are
(a) \( 18, \frac{1}{3} \)
(b) \( 36, \frac{1}{3} \)
(c) \( 36, \frac{2}{3} \)
(d) \( 18, \frac{2}{3} \)
Answer: (b) \( 36, \frac{1}{3} \)
Question. If the mean and variance of a binomial variate X are 8 and 4 respectively then \( P(X < 3) = \) (EAM-2014)
(a) \( \frac{137}{2^{16}} \)
(b) \( \frac{697}{2^{16}} \)
(c) \( \frac{265}{2^{16}} \)
(d) \( \frac{265}{2^{15}} \)
Answer: (a) \( \frac{137}{2^{16}} \)
Question. The mean and standard deviation of a binomial variate X are 4 and \( \sqrt{3} \) respectively. Then \( P(X \ge 1) = \) (EAM-2007)
(a) \( 1 - \left(\frac{1}{4}\right)^{16} \)
(b) \( 1 - \left(\frac{3}{4}\right)^{16} \)
(c) \( 1 - \left(\frac{2}{3}\right)^{16} \)
(d) \( 1 - \left(\frac{1}{3}\right)^{16} \)
Answer: (b) \( 1 - \left(\frac{3}{4}\right)^{16} \)
Question. If the mean and variance of a binomial variable X are 2 and 1 respectively, then \( P(X \ge 1) = \) (EAM-2010)
(a) \( \frac{2}{3} \)
(b) \( \frac{15}{16} \)
(c) \( \frac{7}{8} \)
(d) \( \frac{4}{5} \)
Answer: (b) \( \frac{15}{16} \)
Question. X follows a binomial distribution with parameters \( n=6 \) and \( p \). If \( 4P(X=4)=P(X=2) \). Then \( p = \) (EAM-2009)
(a) \( \frac{1}{2} \)
(b) \( \frac{1}{4} \)
(c) \( \frac{1}{6} \)
(d) \( \frac{1}{3} \)
Answer: (d) \( \frac{1}{3} \)
Question. Suppose X follows a binomial distribution with parameters n and p, where 0 < p < 1. If \( \frac{P(X=r)}{P(X=n-r)} \) is independent of n for every r, then p = (EAM-2012)
(a) 1/2
(b) 1/3
(c) 1/4
(d) 1/8
Answer: (a) 1/2
Question. For a binomial distribution if \( p = \frac{1}{4}, n = 20 \) the probability of mode is
(a) \( ^{20}C_{5} \left(\frac{3}{4}\right)^{5} \)
(b) \( ^{20}C_{5} \left(\frac{1}{4}\right)^{5} \left(\frac{3}{4}\right)^{15} \)
(c) \( ^{10}C_{10} \left(\frac{1}{4}\right)^{10} \left(\frac{3}{4}\right)^{10} \)
(d) \( ^{10}C_{10} \left(\frac{3}{4}\right)^{10} \)
Answer: (b) \( ^{20}C_{5} \left(\frac{1}{4}\right)^{5} \left(\frac{3}{4}\right)^{15} \)
Question. In a B.D. \( n = 400, p = \frac{1}{5} \). Its standard deviation is
(a) \( 10 \times \sqrt{2} \)
(b) \( \frac{1}{800} \)
(c) 4
(d) 8
Answer: (d) 8
Question. If X be B.V. with \( E(X) = 5 \) and \( E(X^{2}) - \{E(X)\}^{2} = 4 \), then the parameters of distribution are
(a) \( \frac{1}{4}, 20 \)
(b) \( \frac{1}{5}, 20 \)
(c) \( \frac{1}{5}, 25 \)
(d) \( \frac{4}{5}, 25 \)
Answer: (c) \( \frac{1}{5}, 25 \)
Question. If x is \( B\left(n, \frac{1}{3}\right), P(x \geq 1) > 0.8 \), the least value of n is
(a) 3
(b) 4
(c) 5
(d) 6
Answer: (b) 4
Question. A box contains 'a' white and 'b' black balls. 'c' balls are drawn at random with replacement. The expected number of white balls drawn is
(a) \( \frac{a}{a+b} \)
(b) \( \frac{ac}{a+b} \)
(c) \( \frac{bc}{a+b} \)
(d) \( \frac{b}{a+b} \)
Answer: (b) \( \frac{ac}{a+b} \)
Question. 5 cards are drawn one after another successively with replacement from a well shuffled pack of 52 cards. The probability that all the 5 cards are spades
(a) \( \left(\frac{3}{4}\right)^{5} \)
(b) \( 1 - \left(\frac{3}{4}\right)^{5} \)
(c) \( \left(\frac{1}{4}\right)^{5} \)
(d) \( 1 - \left(\frac{1}{4}\right)^{5} \)
Answer: (c) \( \left(\frac{1}{4}\right)^{5} \)
Question. A card is drawn and replaced four times from an ordinary pack of 52 playing cards. The probability that at least once heart is drawn
(a) \( \left(\frac{3}{4}\right)^{4} \)
(b) \( 1 - \left(\frac{1}{2}\right)^{4} \)
(c) \( 1 - \left(\frac{3}{4}\right)^{4} \)
(d) \( \left(\frac{1}{2}\right)^{4} \)
Answer: (c) \( 1 - \left(\frac{3}{4}\right)^{4} \)
Question. Out of 800 families with 4 children each the expected number of families having 2 boys and 2 girls is
(a) 100
(b) 200
(c) 300
(d) 400
Answer: (c) 300
Question. One hundred identical coins each with probability P of showing up heads are tossed. If O<P<1 and the probability of heads showing on 50 coins is equal to that of heads showing on 51 coins then the value of P is
(a) \( \frac{50}{100} \)
(b) \( \frac{51}{101} \)
(c) \( \frac{52}{101} \)
(d) \( \frac{53}{101} \)
Answer: (b) \( \frac{51}{101} \)
Question. 2K+1 coins (K is an integer) each with probability P(O<P<1) of getting head are tossed together. If the probability of getting K heads is equal to the probability of getting K+1 heads, the value of P is
(a) \( \frac{1}{4} \)
(b) \( \frac{1}{3} \)
(c) \( \frac{1}{2} \)
(d) \( \frac{1}{8} \)
Answer: (c) \( \frac{1}{2} \)
Question. A card is drawn and replaced in an ordinary pack of playing cards. The number of times a card must be drawn so that the probability of getting atleast a club card is greater than \( \frac{3}{4} \)
(a) 7
(b) 6
(c) 5
(d) 4
Answer: (c) 5
Question. Out of 2000 families with 4 children, the number of familes you expect to have atleast one boy is
(a) 1875
(b) 750
(c) 1250
(d) 625
Answer: (a) 1875
Question. 6 symmetrical dice are thrown 1458 times. The number of times you expect three dice to show a four or five is
(a) 160
(b) 320
(c) 480
(d) 600
Answer: (b) 320
Question. If a sex ratio of births is 49 girls to 51 boys, the probability that there will be 8 girls amongst 10 babies born on the same day in a maternity hospital is
(a) \( ^{10}C_{8} (0.51)^{8} (0.49)^{2} \)
(b) \( ^{10}C_{8} (0.49)^{8} (0.51)^{2} \)
(c) \( ^{10}C_{8} (0.49 \times 0.51)^{8} \)
(d) \( ^{10}C_{8} (0.49 \times 0.51)^{2} \)
Answer: (b) \( ^{10}C_{8} (0.49)^{8} (0.51)^{2} \)
Question. In a market region half of the households is known to use a particular brand of soap. In a household survey, a sample of 10 house holds are alloted to each investigator and 2048 investigators are appointed for the survey. The number of investigators likely to report that there are three households is
(a) 240
(b) 352
(c) 1696
(d) 120
Answer: (a) 240
Question. In a market region half of the households is known to use a particular brand of soap. In a household survey, a sample of 10 house holds are alloted to each investigator and 2048 investigators are appointed for the survey. The number of investigators likely to report that there are atleast 4 users is
(a) 240
(b) 352
(c) 1696
(d) 120
Answer: (c) 1696
Question. The least number of times a fair coin is to be tossed in order that the probability of getting atleast one head is at least 0.99 is
(a) 5
(b) 6
(c) 7
(d) 8
Answer: (c) 7
Question. An arcade game is such that the probability of any person winning is always 0.3. The minimum number of people play the game to ensure that the probability that atleast one person wins is greater than or equal to 0.96 is
(a) 8
(b) 9
(c) 10
(d) 12
Answer: (c) 10
Question. Suppose A and B are two equally strong table tennis players. Which of the following two events is more probable
a) A beats B in exactly 3 games out of 4
b) A beats B in exactly 5 games out of 8
(a) a
(b) b
(c) a & b
(d) neither a nor b
Answer: (a) a
Question. A bag contains 13 balls numbered from 1 to 13. Suppose drawing of an even number is a success. Two balls are drawn with replacement from the bag. The probability of getting two successes is
(a) \( \frac{84}{169} \)
(b) \( \frac{49}{169} \)
(c) \( \frac{36}{169} \)
(d) \( \frac{120}{169} \)
Answer: (c) \( \frac{36}{169} \)
MCQs for Chapter 7 Binomial Theorem Mathematics Class 11
Students can use these MCQs for Chapter 7 Binomial Theorem to quickly test their knowledge of the chapter. These multiple-choice questions have been designed as per the latest syllabus for Class 11 Mathematics released by CBSE. Our expert teachers suggest that you should practice daily and solving these objective questions of Chapter 7 Binomial Theorem to understand the important concepts and better marks in your school tests.
Chapter 7 Binomial Theorem NCERT Based Objective Questions
Our expert teachers have designed these Mathematics MCQs based on the official NCERT book for Class 11. We have identified all questions from the most important topics that are always asked in exams. After solving these, please compare your choices with our provided answers. For better understanding of Chapter 7 Binomial Theorem, you should also refer to our NCERT solutions for Class 11 Mathematics created by our team.
Online Practice and Revision for Chapter 7 Binomial Theorem Mathematics
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